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How to Solve 2^(x - 2) = 3^(2x - 4) Exponential Equation with Different Base with Logarithms
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Strategy to solve Exponential equations with different base
Here is an alternate solution provided by our viewer:
2^(x-2) = 3^(2x-4)
2^(x-2) = 3^(2(x-2))
2^(x-2) = 9^(x-2)
There's no way that a 9^m = 2^m, right? Well, if m = 0, it is possible.
x - 2 = 0
x = 2
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